¿Cómo divides (-6x ^ 4-3x ^ 3-2x ^ 2-4x-7) / (x ^ 2 + 3)?

¿Cómo divides (-6x ^ 4-3x ^ 3-2x ^ 2-4x-7) / (x ^ 2 + 3)?
Anonim

Responder:

#color (azul) ((- - 6x ^ 4-3x ^ 3-2x ^ 2-4x-7) / (x ^ 2 + 3) = - 6x ^ 2-3x + 16 + (5x-55) / (x ^ 2 + 3)) #

Explicación:

# (- 6x ^ 4-3x ^ 3-2x ^ 2-4x-7) / (x ^ 2 + 3) #

El método de la división larga:

# "" "" "" "" "" "" subrayado (-6x ^ 2-3x + 16 "" "" "" "" "" "" "" ") #

# x ^ 2 + 0 * x + 3 | ~ -6x ^ 4-3x ^ 3-2x ^ 2-4x-7 #

# "" "" "" "" "" "" subrayado (-6x ^ 4 + 0 * x ^ 3-18x ^ 2 "" "" "") #

# "" "" "" "" "" "" "" "-3x ^ 3 + 16x ^ 2-4x-7 #

# "" "" "" "" "" "" "" "" subrayado (-3x ^ 3 + 0 * x ^ 2-9x) #

# "" "" "" "" "" "" "" "" "" "16x ^ 2 + 5x-7 #

# "" "" "" "" "" "" "" "" "" "" subrayado (16x ^ 2 + 0 * x + 48) #

# "" "" "" "" "" "" "" "" "" "" "" + 5x-55 larr #Recordatorio

La respuesta

#color (azul) ((- - 6x ^ 4-3x ^ 3-2x ^ 2-4x-7) / (x ^ 2 + 3) = - 6x ^ 2-3x + 16 + (5x-55) / (x ^ 2 + 3)) #