Haz la tabla de verdad de la proposición ¬q [(pΛq) V ~ p]?

Haz la tabla de verdad de la proposición ¬q [(pΛq) V ~ p]?
Anonim

Responder:

Vea abajo.

Explicación:

Dado: #not p -> (p ^^ q) vv ~ p #

Operadores logicos:# "no p:" no p, ~ p; "y:" ^^; o: vv #

Tablas lógicas, negación:

#ul (| "" p | "" q | "" ~ p | "" ~ q |) #

# "" T | "" T | "" F | "" F | #

# "" T | "" F | "" F | "" T | #

# "" F | "" T | "" T | "" F | #

# "" F | "" F | "" T | "" T | #

Tablas lógicas, y & o

#ul (| "" p | "" q | "" p ^^ q "" | "" qvvq "" |) #

# | "" T | "" T | "" T "" | "" T "" | #

# | "" T | "" F | "" F "" | "" T "" | #

# | "" F | "" T | "" F "" | "" T "" | #

# | "" F | "" F | "" F "" | "" F "" | #

Tablas lógicas, si entonces:

#ul (| "" p | "" q | "" p-> q "" |) #

# | "" T | "" T | "" T "" | #

# | "" T | "" F | "" F "" | #

# | "" F | "" T | "" T "" | #

# | "" F | "" F | "" T "" | #

Dada proposición lógica parte 1:

#ul (| "" p ^^ q "" | "" ~ p "" | "" (p ^^ q) vv ~ p |) #

# | "" T "" | "" F "" | "" T "" | #

# | "" F "" | "" F "" | "" F "" | #

# | "" F "" | "" T "" | "" T "" | #

# | "" F "" | "" T "" | "" T "" | #

Dada proposición lógica parte 2:

#ul (| "" ~ q "" | "" (p ^^ q) vv ~ p | "" ~ q -> (p ^^ q) vv ~ p |) #

# | "" F "" | "" T "" | "" T "" | #

# | "" T "" | "" F "" | "" F "" | #

# | "" F "" | "" T "" | "" T "" | #

# | "" T "" | "" T "" | "" T "" | #